How do I set advance file association in Windows 10 (while passing app parameter to open)

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I’m trying to set default to open Tableau workbooks with a connector option, and using connector argument before filename, am I doing the below right?

Below from the command prompt is working fine

"C:\Program Files\Tableau\Tableau 2019.1\bin\tableau.exe" -DConnectPluginsPath=C:\Users\Administrator\AppData\Roaming\connector C:\Users\Administrator\Desktop\Book1.twb

But not working using ftype association

ftype myfile="C:\Program Files\Tableau\Tableau 2019.1\bin\tableau.exe -DConnectPluginsPath=C:\Users\Administrator\AppData\Roaming\connector" %1
assoc .twb=myfile
regsvr32 /i shell32.dll

Seems like it’s not accepting the argument

-DConnectPluginsPath=C:\Users\Administrator\AppData\Roaming\connector

Seems like it’s accepting the parameter after starting app, not while starting app using those parameter settings.

Thanks

Answer

As an alternate, use this REG.exe command-line:

reg add hkcr\myfile\shell\open\command /ve /d "\"C:\Program Files\Tableau\Tableau 2019.1\bin\tableau.exe\" -DConnectPluginsPath=C:\Users\Administrator\AppData\Roaming\connector "\"%1\""

This sets the (default) value to the following:

"C:\Program Files\Tableau\Tableau 2019.1\bin\tableau.exe" -DConnectPluginsPath=C:\Users\Administrator\AppData\Roaming\connector "%1"

Under this registry key:

HKEY_CLASSES_ROOT\myfile\Shell\Open\Command

And then run:

assoc .twb=myfile

Attribution
Source : Link , Question Author : Manu Batham , Answer Author : w32sh

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